JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
For a given reaction \(\mathrm{R} \rightarrow \mathrm{P}, \mathrm{t}_{1 / 2}\) is related to \([\mathrm{A}]_0\) as given in table.
Given: \(\log 2=0.30\)
Which of the following is true?
A. The order of the reaction is \(1 / 2\).
B. If \([\mathrm{A}]_0\) is 1 M , then \(\mathrm{t}_{1 / 2}\) is \(200 \sqrt{10} \mathrm{~min}\)
C. The order of the reaction changes to 1 if the concentration of reactant changes from 0.100 M to 0.500 M .
D. \(\mathrm{t}_{1 / 2}\) is 800 min for \([\mathrm{A}]_0=1.6 \mathrm{M}\)
Choose the correct answer from the options given below:
- A A and C Only
- B A, B and D Only
- C C and D Only
- D A and B Only
Answer & Solution
Correct Answer
(B) A, B and D Only
Step-by-step Solution
Detailed explanation
\(\frac{t_1}{2} \propto\left(C_0\right)^{1-\eta}\) \(\frac{t_1}{t_2}=\left(\frac{C_1}{C_2}\right)^{1-\eta} \) \( \Rightarrow \frac{200}{100}=\left(\frac{0.100}{0.025}\right)^{1-\eta} \) \( \Rightarrow 2=(4)^{1-\eta} \) \( (1-\eta)=\frac{1}{2} \) \( \eta=\frac{1}{2} \)…
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