JEE Mains · Chemistry · STD 11 - 8.3. Organic chemistry purification and characterization
In Carius method for estimation of halogens, 180 mg of an organic compound produced 143.5 mg of AgCl . The percentage composition of chlorine in the compound is _______ %.
(Given : molar mass in \(\mathrm{g} \mathrm{mol}^{-1}\) of \(\mathrm{Ag}: 108, \mathrm{Cl}: 35.5\) )
- A 20
- B 40
- C 60
- D 80
Answer & Solution
Correct Answer
(A) 20
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{n}_{\mathrm{Cl}}=\mathrm{n}_{\mathrm{AgCl}}=\frac{143.5 \times 10^{-3}}{143.5}=10^{-3} \\ & \% \mathrm{Cl}=\frac{10^{-3} \times 35.5}{180 \times 10^{-3}} \times 100=19.72\end{aligned}\)
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