JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
In a chemical reaction \(A + 2B \overset K \rightleftharpoons 2C + D\), the initial concentration of \(B\) was \(1.5\) times of \(A\) but the equilibrium concentrations of \(A\) and \(B\) were found to be equal. The equilibrium, constant \((K)\) for the aforesaid chemical reaction is
- A \(4\)
- B \(16\)
- C \(0.25\)
- D \(1\)
Answer & Solution
Correct Answer
(A) \(4\)
Step-by-step Solution
Detailed explanation
\begin{gathered} \quad \quad \quad \quad \quad \quad \quad \quad A\,\,\, + \,\,\,\,\,2B\,\,\,\,\, \rightleftharpoons \,\,\,\,2C\,\,\, + \,\,\,D \hfill \\ Initially\,\,conc.\,\,\,\,\,\,\,\,a\,\,\,\,\,\,\,\,1.5a\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\…
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