JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
At \(298\, \mathrm{~K}\), the enthalpy of fusion of a solid \((\mathrm{X})\) is \(2.8 \,\mathrm{k} \mathrm{J}\, \mathrm{mol}^{-1}\) and the enthalpy of vaporisation of the liquid \((X)\) is \(98.2 \,\mathrm{~kJ}\, \mathrm{~mol}^{-1}\). The enthalpy of sublimation of the substance \((\mathrm{X})\) in \(\mathrm{kJ} \,\mathrm{mol}^{-1}\) is \(.....\) (in nearest integer)
- A \(99\)
- B \(100\)
- C \(101\)
- D \(201\)
Answer & Solution
Correct Answer
(C) \(101\)
Step-by-step Solution
Detailed explanation
\(\Delta \mathrm{H}_{\text {sub }}=\Delta \mathrm{H}_{\text {fus. }}+\Delta \mathrm{H}_{\text {vap. }}\) \(=2.8+98.2\) \(=101\, \mathrm{KJ} / \mathrm{mol}\)
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