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JEE Mains · Chemistry · STD 12 - 2. Electrochemistry

If the conductivity of mercury at \(0^{\circ} \,\mathrm{C}\) is \(1.07 \times 10^{6}\) \(\mathrm{S} \,\mathrm{m}^{-1}\) and the resistance of a cell containing mercury is \(0.243\, \Omega\), then the cell constant of the cell is \(\mathrm{x} \times 10^{4} \,\mathrm{~m}^{-1}\). The value of \(\mathrm{x}\) is ...... .(Nearest integer)

  1. A \(260\)
  2. B \(39\)
  3. C \(26\)
  4. D \(13\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(26\)

Step-by-step Solution

Detailed explanation

\(\mathrm{k}=1.07 \times 10^{6}\, \mathrm{Sm}^{-1}, \quad \mathrm{R}=0.243\, \Omega\) \(\mathrm{G}=\frac{1}{\mathrm{R}}=\frac{1}{0.243}\, \Omega^{-1}\) \(\mathrm{k}=\mathrm{G} \times \mathrm{G}^{*}\)…
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