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JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics

If a reaction follows the Arrhenius equation, the plot \(\ln k\) vs \(1/(RT)\) gives straight line with a gradient \((-y)\) \(unit\). The energy required to activate the reactant is

  1. A \(y/R\,\)unit
  2. B \(y\,\)unit
  3. C \(yR\,\)unit
  4. D \(-y\,\)unit
Verified Solution

Answer & Solution

Correct Answer

(B) \(y\,\)unit

Step-by-step Solution

Detailed explanation

\(\ln \,k = - \frac{{{E_a}}}{{RT}} + \ln \,A\) \(\therefore \) Slope \(= - E_a = -y\)
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