JEE Mains · Chemistry · STD 12 - 6. Haloalkanes and Haloarenes
Identify the correct set of reagents or reaction conditions ' \(\mathrm{X}\) ' and ' \(\mathrm{Y}\) ' in the following set of transformation.
- A \(\mathrm{X}=\) conc.alc. \(\mathrm{NaOH}, 80^{\circ} \mathrm{C}, \mathrm{Y}=\mathrm{Br}_2 / \mathrm{CHCl}_3\)
- B \(\mathrm{X}=\) dil.aq. \(\mathrm{NaOH}, 20^{\circ} \mathrm{C}, \mathrm{Y}=\mathrm{HBr}\) /acetic acid
- C \(\mathrm{X}=\) conc.alc. \(\mathrm{NaOH}, 80^{\circ} \mathrm{C}, \mathrm{Y}=\mathrm{HBr}\) /acetic acid
- D \(\mathrm{X}=\) dil.aq. \(\mathrm{NaOH}, 20^{\circ} \mathrm{C}, \mathrm{Y}=\mathrm{Br}_2 / \mathrm{CHCl}_3\)
Answer & Solution
Correct Answer
(C) \(\mathrm{X}=\) conc.alc. \(\mathrm{NaOH}, 80^{\circ} \mathrm{C}, \mathrm{Y}=\mathrm{HBr}\) /acetic acid
Step-by-step Solution
Detailed explanation
\(1\). \(\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{Br} \xrightarrow[80^{\circ} \mathrm{C}]{\mathrm{X}=\text { conc.alc.NaOH }}\)…
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