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JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
Given
| Reaction | Energy Change (in \(kJ\) ) |
| \(Li(s) \to Li(g)\) | \(161\) |
| \(Li(g) \to Li^+(g)\) | \(520\) |
| \(\frac {1}{2}F_2(g)\,\to F(g)\) | \(77\) |
| \(F(g) + e^- \to F^-(g)\) | (Electron gain enthalpy) |
| \(Li^+ (g) + F^-(g) \to LiF(s)\) | \(-1047\) |
| \(Li (s) + \frac {1}{2}F_2(g)\to LiF(s)\) | \(-617\) |
- A \(-300\)
- B \(-350\)
- C \(-328\)
- D \(-228\)
Answer & Solution
Correct Answer
(C) \(-328\)
Step-by-step Solution
Detailed explanation
Applying Hess's Law \({\Delta _f}{H^o} = {\Delta _{sub}}H + \frac{1}{2}{\Delta _{diss}}H + I.E. + E.A + {\Delta _{lattice}}H\) \({\Delta _f}{H^o} = {\Delta _{sub}}H + \frac{1}{2}{\Delta _{diss}}H + I.E. + E.A + {\Delta _{lattice}}H\)…
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