JEE Mains · Chemistry · STD 11 - 9. Hydricarbon
For the following Friedel Craft's alkylation reaction, which of the statements are correct?
A. Major product is n-propyl benzene.
B. iso-propyl carbocation intermediate is also generated.
C. Multiple substitution is inevitable.
D. Introducing electron-donating substituent on benzene will not produce any alkyl benzene.
Choose the correct answer from the options given below:
- A A and D only
- B B and C only
- C A and C only
- D B and D only
Answer & Solution
Correct Answer
(B) B and C only
Step-by-step Solution
Detailed explanation
In the given Friedel-Crafts alkylation reaction, \(1\)-chloropropane reacts with anhydrous \(\text{AlCl}_3\) to initially form a primary carbocation, the \(n\)-propyl carbocation (\(\text{CH}_3-\text{CH}_2-\text{CH}_2^+\)). This primary carbocation is less stable and undergoes a…
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