JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
For the reaction \(\mathrm{A} \rightarrow \mathrm{B}\) the following graph was obtained. The time required (in seconds) for the concentration of A to reduce to \(2.5 \mathrm{~g} \mathrm{~L}^{-1}\) (if the initial concentration of A was \(50 \mathrm{~g} \mathrm{~L}^{-1}\)) is _______ (Nearest integer)
Given : \(\log 2=0.3010\) [We can assume in a hypothetical situation that the graph is correct, assuming its first order reaction, in reality the question is wrong.]

- A 43
- B 46
- C 49
- D 50
Answer & Solution
Correct Answer
(A) 43
Step-by-step Solution
Detailed explanation
As it is difficult to predict order using data provided in graph. For specific time interval \(0-5 \mathrm{sec}, 5-10 \mathrm{sec}\) and \(10-15 \mathrm{sec}\). order comes to be zero, but graph is not a straight line. Assuming \(1^{\text {st }}\) order kinetics…
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