JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
First order gas phase reaction \(A \rightarrow B + C\)
\(p_i =\) initial pressure of gas A, \(p_t =\) total pressure of the reaction mixture at time \(t\)
Expression of rate constant (\(k\)) is
- A \(\dfrac{1}{t}\ln\dfrac{p_i}{2p_i - p_t}\)
- B \(\dfrac{1}{t}\ln\dfrac{2p_i}{p_i - p_t}\)
- C \(\dfrac{1}{t}\ln\dfrac{p_i}{3p_i - 2p_t}\)
- D \(\dfrac{1}{t}\ln\dfrac{3p_i}{4p_i - p_t}\)
Answer & Solution
Correct Answer
(A) \(\dfrac{1}{t}\ln\dfrac{p_i}{2p_i - p_t}\)
Step-by-step Solution
Detailed explanation
The given reaction is \(A(g) \rightarrow B(g) + C(g)\) At \(t = 0\), the initial pressure of A is \(p_i\) and the pressures of B and C are \(0\). At time \(t\), let the decrease in pressure of A be \(x\). Pressure of A \(= p_i - x\) Pressure of B \(= x\) Pressure of C \(= x\)…
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