JEE Mains · Chemistry · STD 12 -8.1. Aldehydes and ketones
An organic compound "\(x\)" where molar ratio of C, O and H are equal, on treatment with \(50\%\) KOH under reflux followed by acidification produced "\(y\)". The most likely structure of "\(y\)" is:
[Molar mass of '\(x\)' is \(58\) g mol\(^{-1}\)]
- A \(CH_2 = CH - \overset{O}{\underset{\|}{C}} - OH\)
- B \(CH_3 - CH = CH - CH = O\)
- C \(O = C - OH, \, CH_2 - OH\) (with C-C bond)
- D \(CH_3 - \overset{O}{\underset{\|}{C}} - OH\)
Answer & Solution
Correct Answer
(C) \(O = C - OH, \, CH_2 - OH\) (with C-C bond)
Step-by-step Solution
Detailed explanation
Given the molar ratio of C, O, and H in compound \(x\) is equal, the empirical formula is \(CHO\). Empirical mass \(= 12 + 1 + 16 = 29\) g mol\(^{-1}\). Since the molar mass of \(x\) is \(58\) g mol\(^{-1}\), the molecular formula is \((CHO)_2\) or \(C_2H_2O_2\). The structure…
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