JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
Data given for the following reaction is as follows: \(\mathrm{FeO}_{(0)}+\mathrm{C}_{\text {(gaplike) }} \longrightarrow \mathrm{Fe}_{(0)}+\mathrm{CO}_{(\mathrm{g})}\)
| Substance | \(\Delta \mathrm{H}^{\circ}\) \(\left(\mathrm{kJ} \mathrm{mol}^{-1}\right)\) | \(\Delta \mathrm{S}^{\circ}\) \(\left(\mathrm{J} \mathrm{mol}^{-1} \mathrm{~K}^{-1}\right)\) |
| \(\mathrm{FeO}_{(s)}\) | \(-266.3\) | \(57.49\) |
| \(\mathrm{C}_{\text {(graphite) }}\) | \(0\) | \(5.74\) |
| \(\mathrm{Fe}_{(s)}\) | \(0\) | \(27.28\) |
| \(\mathrm{CO}_{(\mathrm{g})}\) | \(-110.5\) | \(197.6\) |
- A \(964\)
- B \(864\)
- C \(96.4\)
- D \(9.64\)
Answer & Solution
Correct Answer
(A) \(964\)
Step-by-step Solution
Detailed explanation
\(\mathrm{T}_{\min }=\left(\frac{\Delta^{0} \mathrm{H}}{\Delta^{0} \mathrm{~S}}\right)\) \(\Delta^{0} \mathrm{H}_{\mathrm{rxn}}=\left[\Delta_{\mathrm{f}}^{0} \mathrm{H}(\mathrm{Fe})+\Delta_{\mathrm{f}}^{0} \mathrm{H}(\mathrm{CO})\right]-\)…
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