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JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry

The difference in the number of unpaired electrons of a metal ion in its high-spin and low-spin octahedral complexes is two. The metal ion is

  1. A \(Ni^{2+}\)
  2. B \(Fe^{2+}\)
  3. C \(Co^{2+}\)
  4. D \(Mn^{2+}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(Co^{2+}\)

Step-by-step Solution

Detailed explanation

\(Co^{2+}\) high spin \(t_{2g}^5\, e_g^2\, ‘3’\) unpaired electrons \(Co^{2+}\) low spin \(t_{2g}^6\, e_g^1\, ‘1’\) unpaired electron Difference is \(3 -1 = 2\)
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