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JEE Mains · Chemistry · STD 12 - 4. d and f- block elements
A transition metal ' \(\mathrm{M}\) ' among \(\mathrm{Sc}, \mathrm{Ti}, \mathrm{V}, \mathrm{Cr}, \mathrm{Mn}\) and \(\mathrm{Fe}\) has the highest second ionisation enthalpy. The spin only magnetic moment value of \(\mathrm{M}^{+}\)ion is _______ \(\mathrm{BM}\). (Near integer) (Given atomic number \(\mathrm{Sc}: 21, \mathrm{Ti}: 22, \mathrm{~V}: 23, \mathrm{Cr}\) : \(24, \mathrm{Mn}: 25, \mathrm{Fe}: 26)\)
- A \(5\)
- B \(6\)
- C \(9\)
- D \(10\)
Answer & Solution
Correct Answer
(B) \(6\)
Step-by-step Solution
Detailed explanation
Among given metals, \(\mathrm{Cr}\) has maximum \(\mathrm{IE}_2\) because Second electron is removed from stable configuration \(3 \mathrm{~d}^5\) \(\mathrm{Cr}^{+}:[\mathrm{Ar}] 3 \mathrm{~d}^5 4 \mathrm{~s}^0\) \(\therefore\) No of unpaired \(\mathrm{e}^{-}\)in…
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