JEE Mains · Chemistry · STD 11 - 3. Classification of elements and periodicity in properties
\(B\) has a smaller first ionization enthalpy than \(Be\). Consider the following statements : \((I)\) It is easier to remove \(2 \mathrm{p}\) electron than \(2 \mathrm{s}\) electron \((II)\) \(2 \mathrm{p}\) electron of \(\mathrm{B}\) is more shielded from the nucleus by the inner core of electrons than the \(2 s\) electrons of \(Be.\) \((III)\; 2 s\) electron has more penetration power than \(2 \mathrm{p}\) electron. \((IV)\) atomic radius of \(\mathrm{B}\) is more than \(\mathrm{Be}\) (Atomic number \(\mathrm{B}=5, \mathrm{Be}=4\) ) The correct statements are
- A \((I), (II)\) and \((III)\)
- B \((II), (III)\) and \((IV)\)
- C \((I), (III)\) and \((IV)\)
- D \((I), (II)\) and \((IV)\)
Answer & Solution
Correct Answer
(A) \((I), (II)\) and \((III)\)
Step-by-step Solution
Detailed explanation
\(\mathrm{Be} \Rightarrow 1 \mathrm{s}^{2} 2 \mathrm{s}^{2}\) \(\mathrm{B} \Rightarrow 1 \mathrm{s}^{2} 2 \mathrm{s}^{2} 2 \mathrm{p}^{1}\) \(\mathrm{B}\) has a smaller size than \(Be\) it is easier to remove \(2 \mathrm{p}\) electron than \(2 \mathrm{s}\) electron due to less…
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