JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
A solution is prepared by dissolving \(0.6\, g\) of urea (molar mass \(= 60\, g\, mol^{-1}\)) and \(1.8\, g\) of glucose (molar mass \(= 180\, g\, mol^{-1}\)) in \(100\, mL\) of water at \(27\,^oC\). The osmotic pressure of the solution is : ............. \(\mathrm{atm}\) \((R = 0.08206\, L\, atm\, K^{-1}\, mol^{-1})\)
- A \(8.2\)
- B \(1.64\)
- C \(4.92\)
- D \(2.46\)
Answer & Solution
Correct Answer
(C) \(4.92\)
Step-by-step Solution
Detailed explanation
\(\pi \, = \,CRT\, = \,\left( {\frac{6}{{10}}\, + \,\frac{{18}}{{180}}} \right)\, \times \,0.0821\, \times \,300\) \( = \,0.2\, \times \,0.082\, \times \,300\, = \,4.926\,atm.\)
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