JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
A set of solutions is prepared using \(180\) \(g\) of water as a solvent and \(10\) \(g\) of different non-volatile solutes \(A, B\) and \(C\). The relative lowering of vapour pressure in the presence of these solutes are in the order [Given, molar mass of \(A =100 \,g\, mol ^{-1} ; B =200 \,g\, mol ^{-1}\)\(\left. C =10,000 \,g\, mol ^{-1}\right]\)
- A \(A>B>C\)
- B \(A>C>B\)
- C \(C>B>A\)
- D \(B > C > A\)
Answer & Solution
Correct Answer
(A) \(A>B>C\)
Step-by-step Solution
Detailed explanation
Relative lowering of \(V . P. =\frac{\Delta P }{ P ^{0}}= x _{\text {solute }}\)…
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