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JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry

A sample of \(4.5\,mg\) of an unknown monohydric alcohol, \(R - OH\) was added to methylmagnesium iodide. A gas is evolved and is collected and its volume measured to be \(3.1\,mL\). The molecular weight of the unknown alcohol is \(g / mol\). [Nearest integer]

  1. A \(33\)
  2. B \(32\)
  3. C \(31\)
  4. D \(30\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(33\)

Step-by-step Solution

Detailed explanation

\(ROH + CH _{3} MgI \rightarrow ROMgI + CH _{4}( g )\) moles of \(CH _{4}=\) moles of \(ROH\) \(\frac{ V }{22400}=\frac{ m }{ M \cdot M }\) (Assuming NTP Condition) \(\frac{3.1}{22400}=\frac{4.5 \times 10^{-3}}{ M.M }\) \(MM =32.51\) Nearest Integer \(=33\)
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