JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
A sample of \(4.5\,mg\) of an unknown monohydric alcohol, \(R - OH\) was added to methylmagnesium iodide. A gas is evolved and is collected and its volume measured to be \(3.1\,mL\). The molecular weight of the unknown alcohol is \(g / mol\). [Nearest integer]
- A \(33\)
- B \(32\)
- C \(31\)
- D \(30\)
Answer & Solution
Correct Answer
(A) \(33\)
Step-by-step Solution
Detailed explanation
\(ROH + CH _{3} MgI \rightarrow ROMgI + CH _{4}( g )\) moles of \(CH _{4}=\) moles of \(ROH\) \(\frac{ V }{22400}=\frac{ m }{ M \cdot M }\) (Assuming NTP Condition) \(\frac{3.1}{22400}=\frac{4.5 \times 10^{-3}}{ M.M }\) \(MM =32.51\) Nearest Integer \(=33\)
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