JEE Mains · Chemistry · STD 12 - 4. d and f- block elements
A first row transition metal with highest enthalpy of atomisation, upon reaction with oxygen at high temperature forms oxides of formula \(\mathrm{M}_2 \mathrm{O}_{\mathrm{n}}\) (where \(\mathrm{n}=3,4,5\) ). The 'spin-only' magnetic moment value of the amphoteric oxide from the above oxides is. . . . . . ..\(\mathrm{BM}\) (near integer) (Given atomic number: \(\mathrm{Sc}: 21, \mathrm{Ti}: 22, \mathrm{~V}: 23\), \(\mathrm{Cr}: 24, \mathrm{Mn}: 25, \mathrm{Fe}: 26, \mathrm{Co}: 27, \mathrm{Ni}: 28, \mathrm{Cu}: 29\), \(\mathrm{Zn}: 30)\)
- A \(1\)
- B \(2\)
- C \(3\)
- D \(0\)
Answer & Solution
Correct Answer
(D) \(0\)
Step-by-step Solution
Detailed explanation
\(\mathrm{V}\) ' has highest enthalpy of atomisation ( \(515 \mathrm{~kJ} / \mathrm{mol}\) ) among first row transition elements. \(\mathrm{V}_2 \mathrm{O}_5\) Here ' \(\mathrm{V}\) ' is in \(+5\) oxidation state…
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