JEE Mains · Chemistry · STD 12 - 4. d and f- block elements
The correct order of spin only magnetic moments for the following complex ions is
- A \({\left[ Fe ( CN )_6\right]^{3-} < \left[ CoF _6\right]^{3-} < \left[ MnBr _4\right]^{2-}} < \left[ Mn ( CN )_6\right]^{3-}\)
- B \({\left[ Fe ( CN )_6\right]^{3-} < \left[ Mn ( CN )_6\right]^{3-} < \left[ CoF _6\right]^{3-}} < \left[ MnBr _4\right]^{2-}\)
- C \({\left[ MnBr _4\right]^{2-} < \left[ CoF _6\right]^{3-} < \left[ Fe ( CN )_6\right]^{3-}} < \left[ Mn ( CN )_6\right]^{3-}\)
- D \({\left[ CoF _6\right]^{3-} < \left[ MnBr _4\right]^{2-} < \left[ Fe ( CN )_6\right]^{3-}} < \left[ Mn ( CN )_6\right]^{3-}\)
Answer & Solution
Correct Answer
(B) \({\left[ Fe ( CN )_6\right]^{3-} < \left[ Mn ( CN )_6\right]^{3-} < \left[ CoF _6\right]^{3-}} < \left[ MnBr _4\right]^{2-}\)
Step-by-step Solution
Detailed explanation
Spin magnetic moment \(\mu=\sqrt{n(n+2)}\) B.M
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