JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
\(2 \mathrm{SO}_{2}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{SO}_{3}(\mathrm{~g})\) In an equilibrium mixture, the partial pressures are \(P_{S O_{3}}=43\,\mathrm{kPa} ; \quad P_{O_{2}}=530 \,\mathrm{~Pa}\) and \(\mathrm{P}_{\mathrm{SO}_{2}}=45\, \mathrm{kPa}\) The equilibrium constant \(\mathrm{K}_{\mathrm{p}}=......\times 10^{-2} .\) (Nearest integer)
- A \(498\)
- B \(123\)
- C \(745\)
- D \(172\)
Answer & Solution
Correct Answer
(D) \(172\)
Step-by-step Solution
Detailed explanation
\(2 \mathrm{SO}_{2(9)}+\mathrm{O}_{2(\mathrm{~g})}=2 \mathrm{SO}_{3(9)}\) \(\mathrm{K}_{\mathrm{p}}=\frac{\left(\mathrm{pSO}_{3(9)}\right)^{2}}{\mathrm{pSO}_{2(\mathrm{~g})}} \times \mathrm{pO}_{2(\mathrm{~g})}\)…
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