JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
The ratio \(\frac{K_P}{K_C}\) for the reaction : \(CO _{( g )}+\frac{1}{2} O _{2(g)} \rightleftharpoons CO _{2(g)}\) is _______.
- A \(\frac{1}{\sqrt{ RT }}\)
- B \(( RT )^{1 / 2}\)
- C RT
- D 1
Answer & Solution
Correct Answer
(A) \(\frac{1}{\sqrt{ RT }}\)
Step-by-step Solution
Detailed explanation
\(\Delta n_g = n_{products, g} - n_{reactants, g}\) \(\Delta n_g = 1 - (1 + \frac{1}{2})\) \(\Delta n_g = 1 - 1.5 = -0.5\) \(\frac{K_P}{K_C} = (RT)^{\Delta n_g}\) \(\frac{K_P}{K_C} = (RT)^{-0.5}\) \(\frac{K_P}{K_C} = \frac{1}{\sqrt{RT}}\)
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