JEE Advanced · Physics · 22. AC Circuits
You are given many resistances, capacitors and inductors. These are connected to a variable DC voltage source (the first two circuits) or an AC voltage source of \(50 \mathrm{~Hz}\) frequency (the next three circuits) in different ways as shown in Column II. When a current \(I\) (steady state for DC or rms for \(A C\) ) flows through the circuit, the corresponding voltage \(V_1\) and \(V_2\) (indicated in circuits) are related as shown in Column I. Match the two

- A (A) R,S,T, (B) Q,R,T, (C) P, (D) Q,R,S
- B (A) R,S,T, (B) Q,R,S,T, (C) P,Q, (D) Q,R,S,T
- C (A) S,T, (B) Q,R,T, (C) P,Q, (D) Q,R,S,T
- D (A) S,T, (B) Q,R,S,T, (C) P, (D) Q,R,S
Answer & Solution
Correct Answer
(B) (A) R,S,T, (B) Q,R,S,T, (C) P,Q, (D) Q,R,S,T
Step-by-step Solution
Detailed explanation
In circuit (P), I can't be non zero in steady state.
In circuit (Q) :
\(V_1=0\) and \(V_2=2 I=V\) (also)
\(
\begin{aligned}
& \text { In circuit (R): } V_1=X_L I=(2 \pi f \mathrm{~L}) I \\
& \quad=\left(2 \pi \times 50 \times 6 \times 10^{-3}\right) I \\
& \quad=1.88 I \\
& V_2=2 I
\end{aligned}
\)
In circuit (S): \(V_1=X_L I=1.88 I\)
\(
\begin{array}{r}
V_2=X_C I=\left(\frac{1}{2 \pi f C}\right) I \\
=\left(\frac{1}{2 \pi \times 50 \times 3 \times 10^{-6}}\right) I=(1061) I
\end{array}
\)
In circuit (T):
\(
\begin{aligned}
& V_1=I R=(1000) I \\
& V_2=X_C I=(1061) I
\end{aligned}
\)
Therefore the correct options are as under
(A) \(\rightarrow\) R, S, T \(\quad\) (B) \(\rightarrow\) Q, R, S, T
(C) \(\rightarrow\) Q or \(P, Q \quad\) (D) \(\rightarrow\) Q, R, S, T
In circuit (Q) :
\(V_1=0\) and \(V_2=2 I=V\) (also)
\(
\begin{aligned}
& \text { In circuit (R): } V_1=X_L I=(2 \pi f \mathrm{~L}) I \\
& \quad=\left(2 \pi \times 50 \times 6 \times 10^{-3}\right) I \\
& \quad=1.88 I \\
& V_2=2 I
\end{aligned}
\)
In circuit (S): \(V_1=X_L I=1.88 I\)
\(
\begin{array}{r}
V_2=X_C I=\left(\frac{1}{2 \pi f C}\right) I \\
=\left(\frac{1}{2 \pi \times 50 \times 3 \times 10^{-6}}\right) I=(1061) I
\end{array}
\)
In circuit (T):
\(
\begin{aligned}
& V_1=I R=(1000) I \\
& V_2=X_C I=(1061) I
\end{aligned}
\)
Therefore the correct options are as under
(A) \(\rightarrow\) R, S, T \(\quad\) (B) \(\rightarrow\) Q, R, S, T
(C) \(\rightarrow\) Q or \(P, Q \quad\) (D) \(\rightarrow\) Q, R, S, T
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