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JEE Advanced · Mathematics · 17. Properties of Triangles

In a triangle ABC, let AB=23,BC=3 and CA=4. Then the value of cotA+cotCcotB is

  1. A 1
  2. B 3
  3. C 8
  4. D 2
Verified Solution

Answer & Solution

Correct Answer

(D) 2

Step-by-step Solution

Detailed explanation

cotA+cotCcotB=cosAsinA+cosCsinCcosBsinB =cosAsinC+cosCsinAsinAsinC·sinBcosB
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