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JEE Advanced · Physics · 16. Waves & Sound

Two men are walking along a horizontal straight line in the same direction. The man in front walks at a speed 1.0 m s-1 and the man behind walks at a speed 2.0 m s-1 . A third man is standing at a height 12 m above the same horizontal line such that all three men are in a vertical plane. The two walking men are blowing identical whistles which emit a sound of frequency 1430 Hz . The speed of sound in air is 330 m s-1. At the instant, when the moving men are 10 m apart, the stationary man is equidistant from them. The frequency of beats in Hz , heard by the stationary man at this instant, is __________.

  1. A 5
  2. B 7
  3. C 9
  4. D 11
Verified Solution

Answer & Solution

Correct Answer

(A) 5

Step-by-step Solution

Detailed explanation


\(\cos \theta=\frac{5}{13} \)
\( f_A=1430\left[\frac{330}{330-2 \cos \theta}\right]=1430\left[\frac{1}{1-\frac{2 \cos \theta}{333}}\right]\) \(=1430\left[1+\frac{2 \cos \theta}{330}\right] \text { (By binomial expansion) } \)
\( f_B=1430\left[\frac{330}{330+1 \cos \theta}\right]=1430\left[1-\frac{\cos \theta}{330}\right] \)
\( \Delta f=f_A-f_B=1430\left[\frac{3 \cos \theta}{330}\right]=13 \cos \theta \)
\( =13\left(\frac{5}{13}\right)=5.00 H z\)
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