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JEE Advanced · Physics · 22. AC Circuits

A series LCR circuit is connected to a 45 sin(ωt) Volt source. The resonant angular frequency of the circuit is 105 rad s1 and current amplitude at resonance is I0. When the angular frequency of the source is ω=8×104 rad s1, the current amplitude in the circuit is 0.05 I0. If L=50 mH, match each entry in List-I with an appropriate value from List-II and choose the correct option.
  List-I   List-II
P I0 in mA 1 44.4
Q The quality factor of the circuit 2 18
R The bandwidth of the circuit in rad s1 3 400
S The peak power dissipated at resonance in Watt 4 2250
    5 500

  1. A P2, Q3, R5, S1
  2. B P3, Q1, R4, S2
  3. C P4, Q5, R3, S1
  4. D P4, Q2, R1, S5
Verified Solution

Answer & Solution

Correct Answer

(B) P3, Q1, R4, S2

Step-by-step Solution

Detailed explanation

Resonant angular frequency is given by, 1LC=105 150×10-3C=105C=2×10-9 F
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