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JEE Advanced · Physics · 9. Gravitation

Two spherical stars A and B have densities ρA and ρB, respectively. A and B have the same radius, and their masses MA and MB are related by MB=2MA. Due to an interaction process, star A loses some of its mass, so that its radius is halved, while its spherical shape is retained, and its density remains ρA. The entire mass lost by A is deposited as a thick spherical shell on B with the density of the shell being ρA. If vA and vB are the escape velocities from A and B after the interaction process, the ratio vBvA=10n1513. The value of n is

  1. A 2.3
  2. B 2.4
  3. C 2.5
  4. D 2.6
Verified Solution

Answer & Solution

Correct Answer

(A) 2.3

Step-by-step Solution

Detailed explanation

Given here : RA=RB=R and MB=2MA. Now, after interaction process, radius of remaining star A is RA'=R2 and its mass is MA'=ρA43πRA23=MA8
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