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JEE Advanced · Physics · 13. Thermodynamics

One mole of an ideal gas in initial state A undergoes a cyclic process \(A B C A\), as shown in the figure. Its pressure at \(A\) is \(p_0\). Choose the correct option(s) from the following

  1. A Internal energies at \(A\) and \(B\) are the same
  2. B Work done by the gas in process \(A B\) is \(p_0 V_0 \ln 4\)
  3. C Pressure at \(C\) is \(\frac{p_0}{4}\)
  4. D Temperature at \(C\) is \(\frac{T_0}{4}\)
Verified Solution

Answer & Solution

Correct Answer

(B) Work done by the gas in process \(A B\) is \(p_0 V_0 \ln 4\)

Step-by-step Solution

Detailed explanation

\(
\begin{aligned}
& T_A=T_B \quad \therefore U_A=U_B \\
& W_{A B}=(1)(R) T_0 \ln \left(\frac{V_f}{V_i}\right) \\
& =R T_0 \ln \left(\frac{4 V_0}{V_0}\right) \\
& =p_0 V_0 \ln (4)
\end{aligned}
\)
Information regarding \(p\) and \(T\) at \(C\) can not be obtained from the given graph. Unless it is mentioned that line \(B C\) passes through origin or not.
Hence, the correct options are (a) and (b).
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