JEE Advanced · Physics · 15. Oscillations
When two progressive waves \(y_1=4 \sin (2 x-6 t) \quad\) and \(y_2=3 \sin \left(2 x-6 t-\frac{\pi}{2}\right) \quad\) are superimposed, the amplitude of the resultant wave is
- A 3
- B 5
- C 7
- D 9
Answer & Solution
Correct Answer
(B) 5
Step-by-step Solution
Detailed explanation
Phase difference between the two waves is \(90^{\circ}\). Amplitudes are added by vector method.
\(\therefore\) Answer is 5 .
\(\therefore\) Answer is 5 .
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