JEE Advanced · Physics · 13. Thermodynamics
Match the following for the given process


- A (a) s, (b) p, r, (c) r, (d) q,s
- B (a) r, (b) p, s, (c) q, (d) q
- C (a) s, (b) p, r, (c) q, (d) q
- D (a) r, (b) p, s, (c) r, (d) q,s
Answer & Solution
Correct Answer
(A) (a) s, (b) p, r, (c) r, (d) q,s
Step-by-step Solution
Detailed explanation
(a) \(\rightarrow \mathrm{s}\) (b) \(\rightarrow \mathrm{p}, \mathrm{r}\), (c) \(\rightarrow \mathrm{r}\) (d) \(\rightarrow \mathrm{q}, \mathrm{s}\)
In process \(\mathbf{J} \rightarrow \mathbf{K}: V\) is constant whereas \(P\) is decreasing, Therefore, \(T\) should also decrease.
\(\therefore W=0, \Delta U=-\text { ve and } Q < 0\)
In process \(\mathbf{K} \rightarrow \mathbf{L}: P\) is constant while \(V\) is increasing. Therefore, temperature should also increase.
\(\therefore W>0, \Delta U>0 \text { and } Q>0\)
In process \(\mathbf{L} \rightarrow \mathbf{M}\) : This is inverse of process \(J \rightarrow K\).
\(\therefore W=0, \Delta U>0 \text { and } Q>0\)
In process \(\mathbf{M} \rightarrow \mathbf{J}: V\) is decreasing. Therefore, \(W < 0\)
\((P \mathrm{~V})_J < (P V)_M \)
\( \therefore T_J < T_M \text { or } \quad \Delta U < 0 \)
\( \text { Therefore, } Q < 0.\)
No, solution is required.
In process \(\mathbf{J} \rightarrow \mathbf{K}: V\) is constant whereas \(P\) is decreasing, Therefore, \(T\) should also decrease.
\(\therefore W=0, \Delta U=-\text { ve and } Q < 0\)
In process \(\mathbf{K} \rightarrow \mathbf{L}: P\) is constant while \(V\) is increasing. Therefore, temperature should also increase.
\(\therefore W>0, \Delta U>0 \text { and } Q>0\)
In process \(\mathbf{L} \rightarrow \mathbf{M}\) : This is inverse of process \(J \rightarrow K\).
\(\therefore W=0, \Delta U>0 \text { and } Q>0\)
In process \(\mathbf{M} \rightarrow \mathbf{J}: V\) is decreasing. Therefore, \(W < 0\)
\((P \mathrm{~V})_J < (P V)_M \)
\( \therefore T_J < T_M \text { or } \quad \Delta U < 0 \)
\( \text { Therefore, } Q < 0.\)
No, solution is required.
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