JEE Advanced · Chemistry · 23. Coordination Compounds

Match the electronic configurations in List-I with appropriate metal complex ions in List-II and choose the correct option.[Atomic Number: $Fe = 26, Mn = 25, Co = 27$ ]

List I List II

$P$ $t_{2 g}^{6} e_{g}^{0}$ $1$ ${[Fe {(H_{2} O)}_{6}]}^{2 +}$

$Q$ $t_{2 g}^{3} e_{g}^{2}$ $2$ ${[Mn {(H_{2} O)}_{6}]}^{2 +}$

$R$ $e^{2} t_{2}^{3}$ $3$ ${[Co {({NH}_{3})}_{6}]}^{3 +}$

$S$ $t_{2 g}^{4} e_{g}^{2}$ $4$ ${[{FeCl}_{4}]}^{-}$

$5$ ${[{CoCl}_{4}]}^{2 -}$

A $P \to 1; Q \to 4; R \to 2; S \to 3$
B $P \to 1; Q \to 2; R \to 4; S \to 5$
C $P \to 3; Q \to 2; R \to 5; S \to 1$
D $P \to 3; Q \to 2; R \to 4; S \to 1$

Verified Solution

Answer & Solution

Correct Answer

(D) $P \to 3; Q \to 2; R \to 4; S \to 1$

Step-by-step Solution

Detailed explanation

In the complex

{[Fe {(H_{2} O)}_{6}]}^{2 +}

the electronic configuration of

{Fe}^{2 +}

[Ar] 3 d^{6}

H_{2} O

is a weak ligand. Hence, the crystal filed splitting can be shown as follows, In the complex

{[Mn {(H_{2} O)}_{6}]}^{2 +}

the electronic configuration of

{Mn}^{2 +}

[Ar] 3 d^{5}

H_{2} O

is a weak ligand. Hence, the crystal filed splitting can be shown as follows,

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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	List I		List II
$P$	$t_{2 g}^{6} e_{g}^{0}$	$1$	${[Fe {(H_{2} O)}_{6}]}^{2 +}$
$Q$	$t_{2 g}^{3} e_{g}^{2}$	$2$	${[Mn {(H_{2} O)}_{6}]}^{2 +}$
$R$	$e^{2} t_{2}^{3}$	$3$	${[Co {({NH}_{3})}_{6}]}^{3 +}$
$S$	$t_{2 g}^{4} e_{g}^{2}$	$4$	${[{FeCl}_{4}]}^{-}$
		$5$	${[{CoCl}_{4}]}^{2 -}$

Match the electronic configurations in List-I with appropriate metal complex ions in List-II and choose the correct option.[Atomic Number: Fe = 26, Mn = 25, Co = 27] List I List II P t2g6eg0 1 FeH2O62+ Q t2g3eg2 2 MnH2O62+ R e2t23 3 CoNH363+ S t2g4eg2 4 FeCl4- 5 CoCl42-

Step-by-step Solution