JEE Advanced · Physics · 25. Wave Optics
In a Young's double slit experiment, the separation between the two slits is \(d\) and the wavelength of the light is \(\lambda\). The intensity of light falling on slit 1 is four times the intensity of light falling on slit 2 . Choose the correct choice(s),
- A If \(d=\lambda\), the screen will contain only one maximum
- B If \(\lambda < d < 2 \lambda\), at least one more maximum (besides the central maximum) will be observed on the screen
- C If the intensity of light falling on slit 1 is reduced so that it becomes equal to that of slit 2 , the intensities of the observed dark and bright fringes will increase
- D If the intensity of light falling on slit 2 is increased so that it becomes equal to that of slit 1 , the intensities of the observed dark and bright fringes will increase
Answer & Solution
Correct Answer
(B) If \(\lambda < d < 2 \lambda\), at least one more maximum (besides the central maximum) will be observed on the screen
Step-by-step Solution
Detailed explanation
For \(d=\lambda\), there will be only one, acentral maxima.
For \(\lambda < d < 2 \lambda\), there will be three maximas on the screen corresponding to path difference, \(\Delta x=0\) and \(\Delta x=\pm \lambda\) correct options are (a) and (b).
For \(\lambda < d < 2 \lambda\), there will be three maximas on the screen corresponding to path difference, \(\Delta x=0\) and \(\Delta x=\pm \lambda\) correct options are (a) and (b).
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