JEE Advanced · Physics · 19. Current Electricity
Two bars of radius ' \(r\) ' and ' \(2 r\) ' are kept in contact as shown. An electric current \(I\) is passed through the bars. Which one of the following is correct?

- A Heat produced in bar \(B C\) is 4 times the heat produced in bar \(A B\)
- B Electric field in both halves is equal
- C Current density across \(A B\) is doubled that of across \(B C\)
- D Potential difference across \(A B\) is 4 times that of across \(B C\)
Answer & Solution
Correct Answer
(A) Heat produced in bar \(B C\) is 4 times the heat produced in bar \(A B\)
Step-by-step Solution
Detailed explanation
Current flowing through both the bars is equal. Now, the heat produced is given by
\(
\begin{aligned}
H & =I^2 R t \text { or } H \propto R \text { or } \frac{H_{A B}}{H_{B C}}=\frac{R_{A B}}{R_{B C}} \\
& =\frac{\left(\frac{1}{2 r}\right)^2}{\left(\frac{1}{r}\right)^2} \\
& =\frac{1}{4} \text { or } H_{B C}=4 H_{A B}
\end{aligned}
\)
\(\left(\text { as } R \propto \frac{1}{A} \propto \frac{1}{r^2}\right)\)
\(
\begin{aligned}
H & =I^2 R t \text { or } H \propto R \text { or } \frac{H_{A B}}{H_{B C}}=\frac{R_{A B}}{R_{B C}} \\
& =\frac{\left(\frac{1}{2 r}\right)^2}{\left(\frac{1}{r}\right)^2} \\
& =\frac{1}{4} \text { or } H_{B C}=4 H_{A B}
\end{aligned}
\)
\(\left(\text { as } R \propto \frac{1}{A} \propto \frac{1}{r^2}\right)\)
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