JEE Advanced · Physics · 29. Experimental Physics
Figure 1 shows the configuration of main scale and Vernier scale before measurement. Fig. 2 shows the configuration corresponding to the measurement of diameter \(D\) of a tube. The measured value of \(D\) is:

- A 0.12 cm
- B 0.11 cm
- C 0.13 cm
- D 0.14 cm
Answer & Solution
Correct Answer
(C) 0.13 cm
Step-by-step Solution
Detailed explanation
\(\begin{aligned}
& 10 \mathrm{MSD}=1 \mathrm{~cm} ; 1 \mathrm{MSD}=0.1 \mathrm{~cm} \\
& 7 \mathrm{MSD}=10 \mathrm{VSD} \\
& 1 \mathrm{VSD}=0.07 \mathrm{~cm} \\
& \text { Reading }=2 \mathrm{MSD}-\mathrm{VSD} \\
& =0.2 \mathrm{~cm}-0.07 \mathrm{~cm}=0.13 \mathrm{~cm}
\end{aligned}\)
Ans. Option (C)
& 10 \mathrm{MSD}=1 \mathrm{~cm} ; 1 \mathrm{MSD}=0.1 \mathrm{~cm} \\
& 7 \mathrm{MSD}=10 \mathrm{VSD} \\
& 1 \mathrm{VSD}=0.07 \mathrm{~cm} \\
& \text { Reading }=2 \mathrm{MSD}-\mathrm{VSD} \\
& =0.2 \mathrm{~cm}-0.07 \mathrm{~cm}=0.13 \mathrm{~cm}
\end{aligned}\)
Ans. Option (C)
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