JEE Advanced · Chemistry · 1. Mole Concept
The treatment of an aqueous solution of 3.74 g of \(\text{Cu} \left(\text{NO} _3\right)_2\) with excess KI results in a brown solution along with the formation of a precipitate. Passing \(\text{H} _2 \text{S}\) through this brown solution gives another precipitate X . The amount of X (in g ) is _____________ [Given: Atomic mass of \(\text{H} =1, \text{N}=14, \text{O} =16, \text{S}=32, \text{K}=39,\) \(\text{Cu} =63, \text{I} =127]\)
- A 0.32
- B 0.33
- C 0.34
- D 0.35
Answer & Solution
Correct Answer
(A) 0.32
Step-by-step Solution
Detailed explanation
Number of moles of
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