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JEE Advanced · Mathematics · 19. Determinants

Consider the system of equations \(x-2 y+3 z=-1, x-3 y+4 z=1\) and \(-x+y-2 z=k\)
Statement 1 The system of equations has no solution for \(k \neq 3\).
Statement 2 The determinant \(\left|\begin{array}{ccc}1 & 3 & -1 \\ -1 & -2 & k \\ 1 & 4 & 1\end{array}\right| \neq 0\), for \(k \neq 3\).

  1. A
    Statement 1 is true, Statement 2 is true, Statement 2 is a correct explanation for Statement 1.
  2. B
    Statement 1 is true, Statement 2 is true, Statement 2 is not a correct explanation for Statement 1.
  3. C
    Statement 1 is true, Statement 2 is false.
  4. D
    Statement 1 is false, Statement 2 is true
Verified Solution

Answer & Solution

Correct Answer

(A)
Statement 1 is true, Statement 2 is true, Statement 2 is a correct explanation for Statement 1.

Step-by-step Solution

Detailed explanation

\[
\text { The given system of equations can be expressed as }
\]


When \(k \neq 3\), the given system of equations has no solution.
\(\Rightarrow\) Statement 1 is true.Clearly, Statement 2 is also true as it is rearrangement of rows and columns of

Hence, option (a) is correct.
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