JEE Advanced · Physics · 25. Wave Optics
A point source \(\mathrm{S}\) emits unpolarized light uniformly in all directions. At two points \(\mathrm{A}\) and \(\mathrm{B}\), the ratio \(r=I_A / I_B\) of the intensities of light is 2. If a set of two polaroids having \(45^{\circ}\) angle between their pass-axes is placed just before point \(\mathrm{B}\), then the new value of \(r\) will be ______
- A 2
- B 4
- C 6
- D 8
Answer & Solution
Correct Answer
(D) 8
Step-by-step Solution
Detailed explanation
\(I \propto \frac{1}{l^2}\)
Where I: distance from point source.
\(\begin{aligned}
& \Rightarrow \frac{I_A}{I_B}=\frac{I_B^2}{I_A^2}=2 \\
& \Rightarrow I_B=\sqrt{2} I_A .
\end{aligned}\)
Also, due to polaroids:
\(\begin{aligned}
& I_B^{\prime}=\frac{I_B}{2} \cos ^2 45^{\circ}=\frac{I_B}{4} \\
& \Rightarrow I_B^{\prime}=\frac{I_B}{4} \ldots \text { (2) } \\
& \Rightarrow \text { Ratio becomes } 4 \text { times. } \\
& \Rightarrow r_{\text {new }}=8
\end{aligned}\)
Where I: distance from point source.
\(\begin{aligned}
& \Rightarrow \frac{I_A}{I_B}=\frac{I_B^2}{I_A^2}=2 \\
& \Rightarrow I_B=\sqrt{2} I_A .
\end{aligned}\)
Also, due to polaroids:
\(\begin{aligned}
& I_B^{\prime}=\frac{I_B}{2} \cos ^2 45^{\circ}=\frac{I_B}{4} \\
& \Rightarrow I_B^{\prime}=\frac{I_B}{4} \ldots \text { (2) } \\
& \Rightarrow \text { Ratio becomes } 4 \text { times. } \\
& \Rightarrow r_{\text {new }}=8
\end{aligned}\)
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