JEE Advanced · Mathematics · 27. Definite Integration
The value of \(\frac{(5050) \int_0^1\left(1-x^{50}\right)^{100} d x}{\int_0^1\left(1-x^{50}\right)^{101} d x}\)
- A 1542
- B 1558
- C 5541
- D 5051
Answer & Solution
Correct Answer
(D) 5051
Step-by-step Solution
Detailed explanation
Let \(I_2=\int_0^1\left(1-x^{50}\right)^{101} d x\), using integration by parts
\[
\begin{aligned}
& \left.=\left[(1-x)^{50}\right)^{101} \cdot x\right]_0^1+\int_0^1\left(1-x^{50}\right)^{100} 50 \cdot x^{49} \cdot x d x \\
& =0-\int_0^1(50)(101)\left(1-x^{50}\right)^{100}(-x)^{50} d x \\
& =-(50)(101) \int_0^1\left(1-x^{50}\right)^{101} d x+(50)(101) \int_0^1\left(1-x^{50}\right)^{100} d x \\
& =5050 I_2+5050 I_1
\end{aligned}
\]
\[
\begin{aligned}
\therefore & I_2+5050 I_2 & =5050 I_1 \\
\therefore & \frac{(5050) I_1}{I_2} & =5051
\end{aligned}
\]
\[
\begin{aligned}
& \left.=\left[(1-x)^{50}\right)^{101} \cdot x\right]_0^1+\int_0^1\left(1-x^{50}\right)^{100} 50 \cdot x^{49} \cdot x d x \\
& =0-\int_0^1(50)(101)\left(1-x^{50}\right)^{100}(-x)^{50} d x \\
& =-(50)(101) \int_0^1\left(1-x^{50}\right)^{101} d x+(50)(101) \int_0^1\left(1-x^{50}\right)^{100} d x \\
& =5050 I_2+5050 I_1
\end{aligned}
\]
\[
\begin{aligned}
\therefore & I_2+5050 I_2 & =5050 I_1 \\
\therefore & \frac{(5050) I_1}{I_2} & =5051
\end{aligned}
\]
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