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JEE Advanced · Mathematics · 22. Functions

Let \(\mathbb{R}\) denote the set of all real numbers. Let \(a_{\mathrm{i}}, b_{\mathrm{i}} \in \mathbb{R}\) for \(\mathrm{i} \in\{1,2,3\}\).
Define the functions \(f: \mathbb{R} \rightarrow \mathbb{R}, g: \mathbb{R} \rightarrow \mathbb{R}\), and \(h: \mathbb{R} \rightarrow \mathbb{R}\) by
\(\begin{aligned} & f(x)=a_1+10 x+a_2 x^2+a_3 x^3+x^4, \\ & g(x)=b_1+3 x+b_2 x^2+b_3 x^3+x^4, \\ & h(x)=f(x+1)-g(x+2) .\end{aligned}\)
If \(f(x) \neq g(x)\) for every \(x \in \mathbb{R}\), then the coefficient of \(x^3\) in \(h(x)\) is

  1. A 8
  2. B 2
  3. C -4
  4. D -6
Verified Solution

Answer & Solution

Correct Answer

(C) -4

Step-by-step Solution

Detailed explanation

\(\begin{aligned}
& h(x)=f(x+1)-g(x+2) \\
& =a_1+10(x+1)+a_2(x+1)^2+a_3(x+1)^3+(x+1)^4-b_1-3(x+2)-b_2(x+2)^2-b_3(x+2)^3-(x+2)^4
\end{aligned}\)
Coeff. of \(x^3\) in \(h(x)\)
\(\begin{aligned}
& =a_3-b_3-4 \\
& f(x)-g(x) \neq 0 \quad \forall x \in R \\
& \Rightarrow a_1+10 x+a_2 x^2+a_3 x^3+x^4-b_1-3 x-b_2 x^2-b_3 x^3-x^4 \neq 0 \\
& \Rightarrow x^3\left(a_3-b_3\right)+x^2\left(a_2-b_2\right)+7 x+\left(a_1-b_1\right) \neq 0
\end{aligned}\)
Cubic Eq. will become zero at atleast are value of \(x\)
So it will be quadratic
\(\Rightarrow \mathrm{a}_3-\mathrm{b}_3=0\)
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