JEE Advanced · Mathematics · 13. Parabola
Consider the two curves
\(C_1: y^2=4 x\)
\(C_2: x^2+y^2-6 x+1=0\), then
- A \(C_1\) and \(C_2\) touch each other only at one point
- B \(C_1\) and \(C_2\) touch each other exactly at two points
- C \(C_1\) and \(C_2\) intersect (but do not touch) at exactly two points
- D \(C_1\) and \(C_2\) neither intersect nor touch each other
Answer & Solution
Correct Answer
(B) \(C_1\) and \(C_2\) touch each other exactly at two points
Step-by-step Solution
Detailed explanation

For the points of intersection of the two given curves
\[
C_1: y^2=4 x \text { and } C_2: x^2+y^2-6 x+1=0 \text {, }
\]
we have
\[
\begin{aligned}
& x^2+4 x-6 x+1=0 \\
& \Rightarrow \quad x^2-2 x+1=0 \\
& \Rightarrow \quad(x-1)^2=0 \\
& \Rightarrow \quad x=1,1 \\
& \Rightarrow \quad y=2,-2 \\
&
\end{aligned}
\]
Thus, the given curves touch each other exactly at two points \((1,2)\) and \((1,-2)\).
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