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JEE Advanced · Mathematics · 30. Vector Algebra

Let O be the origin and let PQR be an arbitrary triangle. The pointS is such that OP.OQ+OR.OS=OR.OP+OQ.OS=OQ.OR+OP.OS then triangle PQR has S as its

  1. A Incentre
  2. B Orthocentre
  3. C Circumcentre
  4. D Centroid
Verified Solution

Answer & Solution

Correct Answer

(B) Orthocentre

Step-by-step Solution

Detailed explanation

Let position vector of Pp, Qq, Rr and Sr with respect to Oo

Now, OP . OQ+ OR . OS= OR . OP+ OQ . OS

p.q+ r.s= r.p+ q. s

p- s . q- r=0 .....(i)

Also, OR . OP+ OQ . OS= OQ. OR+ OP . OS

r.p+ q . s= q . r+ p . s

r- s . p- q=0 .....(ii)

Also OP . OQ+ OR . OS= OQ . OR+ OP . OS

p.q+ r. s= q . r+ p. s

q- s . p- r=0 .....(iii)



Triangle PQR has S as its orthocenter

option (Orthocentre) is correct.
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