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JEE Advanced · Mathematics · 29. Differential Eqns

Let f: be a differentiable function with f0=0. If y=fx satisfies the differential equation dydx=2+5y5y-2, then the value of  limx-fx is 

  1. A 0.46
  2. B 0.4
  3. C 0.12
  4. D 0.22
Verified Solution

Answer & Solution

Correct Answer

(B) 0.4

Step-by-step Solution

Detailed explanation

dydx=25y2-4
So  dy25y2-4=dx
Integrating  125×12×25lny-25y+25=x+c
   ln5y-25y+2=20x+c
Now,  c=0 as f0=0
Hence, 5y-25y+2=e20x
limx-5fx-2 5fx+2= limx-e20x
Now,  
RHS=0 lim x ( 5f( x )2 )=0
lim x f( x )= 2 5
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