JEE Advanced · Chemistry · 21. p Block (G15-18)
During sodium nitroprusside test of sulphide ion in an aqueous solution, one of the ligands coordinated to the metal ion is converted to
- A \(\mathrm{NOS}^{-}\)
- B \(\mathrm{SCN}^{-}\)
- C \(\mathrm{SNO}^{-}\)
- D \(\mathrm{NCS}^{-}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{NOS}^{-}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{Na}_2\left[\mathrm{Fe}(\mathrm{CN})_5(\mathrm{NO})\right]+\mathrm{Na}_2 \mathrm{~S} \rightarrow \mathrm{Na}_4[\mathrm{Fe}\) \((\mathrm{CN})_5(\mathrm{NOS})]\)
Sodium nitroprusside purple solution
Sodium nitroprusside purple solution
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