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JEE Advanced · Chemistry · 4. Chemical Bonding

The sum of the number of lone pairs of electrons on each central atom in the following species is \(\left[ TeBr _6\right]^{2-},\left[ Br F _2\right]^{+}, S N F_3\) and \(\left[ XeF _3\right]^{-}\)[Atomic number : \(N=7, F=9, S =16, B r=35,\) \(T e=52, X e=54]\)

  1. A 6
  2. B 12
  3. C 5
  4. D 10
Verified Solution

Answer & Solution

Correct Answer

(A) 6

Step-by-step Solution

Detailed explanation

  Number of σ-bonds formed by central metal atom/ ion Number of lone pairs on central metal atom/ ion
(i)  In TeBr62-  6  1
(ii) InBrF2+   2   2
(iii)  InSNF3  4  0
(iv)  InXeF3-  3  3
    Total number of lone pairs of electrons =1+2+0+3 =6
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