JEE Advanced · Chemistry · 4. Chemical Bonding
The sum of the number of lone pairs of electrons on each central atom in the following species is \(\left[ TeBr _6\right]^{2-},\left[ Br F _2\right]^{+}, S N F_3\) and \(\left[ XeF _3\right]^{-}\)[Atomic number : \(N=7, F=9, S =16, B r=35,\) \(T e=52, X e=54]\)
- A 6
- B 12
- C 5
- D 10
Answer & Solution
Correct Answer
(A) 6
Step-by-step Solution
Detailed explanation
| Number of -bonds formed by central metal atom/ ion | Number of lone pairs on central metal atom/ ion | |
| (i) | 6 | 1 |
| (ii) | 2 | 2 |
| (iii) | 4 | 0 |
| (iv) | 3 | 3 |
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