JEE Advanced · Chemistry · 1. Mole Concept
To check the principle of multiple proportions, a series of pure binary compounds were analysed and their composition is tabulated below. The correct option(s) is(are)
| Compound | Weight of | Weight of |
- A If empirical formula of compound is , then the empirical formula of compound is .
- B If empirical formula of compound is and atomic weight of element is , then the atomic weight of is
- C If empirical formula of compound is , then the empirical formula of the compound is .
- D If atomic weight of and are and , respectively, then the empirical formula of compound is .
Answer & Solution
Correct Answer
(C) If empirical formula of compound is , then the empirical formula of the compound is .
Step-by-step Solution
Detailed explanation
(A) If empirical formula of is , then molecular formula is
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- In a conductometric titration, small volume of titrant of higher concentration is added stepwise to a larger volume of titrate of much lower concentration, and the conductance is measured after each addition.
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Consider a simple \(R C\) circuit as shown in Figure \(1\).
Process 1: In the circuit the switch \(S\) is closed at \(t=0\) and the capacitor is fully charged to voltage \(V_{0}\) (i.e., charging continues for time \(T>>R C\) ). In the process some dissipation \(\left(E_{D}\right)\) occurs across the resistance \(R\). The amount of energy finally stored in the fully charged capacitor is \(E_{C}\).
Process 2: In a different process the voltage is first set to \(\frac{V_{0}}{3}\) and maintained for a charging time \(T>>R C\). Then the voltage is raised to \(\frac{2 V_{0}}{3}\) without discharging the capacitor and again maintained for a time \(T>>R C\). The process is repeated one more time by raising the voltage to \(V_{0}\) and the capacitor is charged to the same final voltage \(V_{0}\) as in Process 1.
These two processes are depicted in Figure \(2 .\)

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