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JEE Advanced · Chemistry · 4. Chemical Bonding

Based on VSEPR theory, the number of 90 degree \(\mathrm{F}-\mathrm{Br}-\mathrm{F}\) angles in \(\mathrm{BrF}_5\) is

  1. A 16
  2. B 8
  3. C 10
  4. D 6
Verified Solution

Answer & Solution

Correct Answer

(B) 8

Step-by-step Solution

Detailed explanation

In \(\mathrm{BrF}_5\) number of electrons \(=6\) \((1 l p+5 b p)\)
So, the structure is supposed to be square pyramidal but will be distorted because of additional lp- \(b p\) interaction.


Additional \(\quad l p-b p\)
interaction reduces the all bond angle and do not let any angle to be \(90^{\circ}\).
Chemical bonding
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