JEE Advanced · Chemistry · 4. Chemical Bonding
Based on VSEPR theory, the number of 90 degree \(\mathrm{F}-\mathrm{Br}-\mathrm{F}\) angles in \(\mathrm{BrF}_5\) is
- A 16
- B 8
- C 10
- D 6
Answer & Solution
Correct Answer
(B) 8
Step-by-step Solution
Detailed explanation
In \(\mathrm{BrF}_5\) number of electrons \(=6\) \((1 l p+5 b p)\)
So, the structure is supposed to be square pyramidal but will be distorted because of additional lp- \(b p\) interaction.

Additional \(\quad l p-b p\)
interaction reduces the all bond angle and do not let any angle to be \(90^{\circ}\).
Chemical bonding
Conceptual
IV
So, the structure is supposed to be square pyramidal but will be distorted because of additional lp- \(b p\) interaction.

Additional \(\quad l p-b p\)
interaction reduces the all bond angle and do not let any angle to be \(90^{\circ}\).
Chemical bonding
Conceptual
IV
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