JEE Advanced · Chemistry · 8. Ionic Equilibrium
The dilution processes of different aqueous solutions with water are given in LIST-I. The effects of dilution of the solutions on are given in LIST-II.
(Note: The degree of dissociation of a weak acid and a weak base is the degree of hydrolysis of salt is represents the concentration of ions)
| List - I | List - II |
| A) 10 mL of \(0.1\text{ M NaOH} +20\text{ mL}\) of 0.1 M acetic acid diluted to 60 mL . | P) The value of \(\left[\text H ^{+}\right]\)does not change on dilution. |
| B) 20 mL of \(0.1\text{ M NaOH} +20\text{ mL}\) of 0.1 M acetic acid diluted to 80 mL . | Q) The value of \(\left[\text H ^{+}\right]\)changes to half of its initial value on dilution. |
| C) 20 mL of \(0.1\text{ M HCl} +20\text{ mL}\) of 0.1 M ammonia solution diluted to 80 mL . | R) The value of \(\left[\text H ^{+}\right]\)changes to two times its initial value on dilution. |
| D) 10 mL saturated solution of \(\text{Ni} (\text{OH})_2\) in equilibrium with excess of solid \(\text{Ni} (\text{OH})_2\) is diluted to 20 mL (solid \(\text{Ni} (\text{OH})_2\) is still present after dilution). | S) The value of \(\left[\text H ^{+}\right]\)changes to \(\sqrt{ }\) times its initial value on dilution. |
| T) The value of \(\left[\text H ^{+}\right]\)changes to \(\sqrt{2}\) times its initial value on dilution. |
Match each process given in LIST-I with one or more effect(s) in LIST-II. The correct option is
- A a-q;b-t;c-p;d-r;
- B a-p;b-t;c-s;d-p;
- C a-s;b-t;c-p;d-r;
- D a-s;b-q;c-p;d-t;
Answer & Solution
Correct Answer
(B) a-p;b-t;c-s;d-p;
Step-by-step Solution
Detailed explanation

will not change on dilution.


Because of dilution, the solubility does not change. So, .
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