ExamBro
ExamBro
JEE Advanced · Chemistry · 8. Ionic Equilibrium

The dilution processes of different aqueous solutions with water are given in LIST-I. The effects of dilution of the solutions on [H+] are given in LIST-II.
(Note: The degree of dissociation α of a weak acid and a weak base is << 1; the degree of hydrolysis of salt is <<1; [H+] represents the concentration of H+ ions)
List - IList - II
A) 10 mL of \(0.1\text{ M NaOH} +20\text{ mL}\) of 0.1 M acetic acid diluted to 60 mL .P) The value of \(\left[\text H ^{+}\right]\)does not change on dilution.
B) 20 mL of \(0.1\text{ M NaOH} +20\text{ mL}\) of 0.1 M acetic acid diluted to 80 mL .Q) The value of \(\left[\text H ^{+}\right]\)changes to half of its initial value on dilution.
C) 20 mL of \(0.1\text{ M HCl} +20\text{ mL}\) of 0.1 M ammonia solution diluted to 80 mL .R) The value of \(\left[\text H ^{+}\right]\)changes to two times its initial value on dilution.
D) 10 mL saturated solution of \(\text{Ni} (\text{OH})_2\) in equilibrium with excess of solid \(\text{Ni} (\text{OH})_2\) is diluted to 20 mL (solid \(\text{Ni} (\text{OH})_2\) is still present after dilution).S) The value of \(\left[\text H ^{+}\right]\)changes to \(\sqrt{ }\) times its initial value on dilution.
T) The value of \(\left[\text H ^{+}\right]\)changes to \(\sqrt{2}\) times its initial value on dilution.

Match each process given in LIST-I with one or more effect(s) in LIST-II. The correct option is

  1. A a-q;b-t;c-p;d-r;
  2. B a-p;b-t;c-s;d-p;
  3. C a-s;b-t;c-p;d-r;
  4. D a-s;b-q;c-p;d-t;
Verified Solution

Answer & Solution

Correct Answer

(B) a-p;b-t;c-s;d-p;

Step-by-step Solution

Detailed explanation

(A)

pH=pKaH+ will not change on dilution.
(B)

OH-=KHC=kwkaC
H+1=kwkaC
H+2H+1=C1C2=0.050.025=2
(C)

H+=KHC
H+2H+1=C2C1=12
(D) Because of dilution, the solubility does not change. So, H+=constant.
Same subject
Explore more questions on app
From JEE Advanced
Explore more questions on app