JEE Advanced · Chemistry · 18. Chemical Kinetics
The concentration of \(R\) in the reaction \(R \longrightarrow P\) was measured as a function of time and the following data is obtained :
\(\begin{array}{lllll}{[R] \text { (molar) }} & 1.0 & 0.75 & 0.40 & 0.10 \\ t \text { (min) } & 0.0 & 0.05 & 0.12 & 0.18\end{array}\)
The order of the reaction is
- A \(0\)
- B 1
- C 2
- D 3
Answer & Solution
Correct Answer
(A) \(0\)
Step-by-step Solution
Detailed explanation
\(k_{\mathrm{I}}=\frac{\Delta[R]}{\Delta t}=\frac{0.25}{0.05}=5\)
\(k_{\text {II }}=\frac{\Delta[R]}{\Delta t}=\frac{0.60}{0.12}=5\)
So, reaction must be of zero order.
Chemical kinetics
Straight conceptual
II
\(k_{\text {II }}=\frac{\Delta[R]}{\Delta t}=\frac{0.60}{0.12}=5\)
So, reaction must be of zero order.
Chemical kinetics
Straight conceptual
II
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