JEE Advanced · Mathematics · 29. Differential Eqns

Let $y (x)$ be a solution of the differential equation $(1 + e^{x}) y^{'} + y e^{x} = 1 .$ If $y (0) = 2$ , then which of the following statements is (are) true?

A $y (- 4) = 0$
B $y (- 2) = 0$
C $y (x)$ has a critical point in the interval (-1, 0)
D $y (x)$ has no critical point in the interval (-1, 0)

Verified Solution

Answer & Solution

Correct Answer

(C) $y (x)$ has a critical point in the interval (-1, 0)

Step-by-step Solution

Detailed explanation

(1 + e^{x}) d y + y e^{x} d x = d x

d y + d (e^{x} . y) = d x

y e^{x} = x - y + c

Now,

x = 0, y = 2

2 . e^{0} = 0 - 2 + c

\Rightarrow c = 4

Now,

y e^{x} = x - y + 4

y = \frac{x + 4}{e^{x} + 1}

Now,

\frac{d y}{d x} = \frac{(e^{x} + 1) - (x + 4) e^{x}}{e^{x} + 1}

= \frac{e^{x} + 1 - x e^{x} - 4 e^{x}}{e^{x} + 1} = \frac{1 - x e^{x} - 3 e^{x}}{e^{x} + 1}

f^{'} (0) = - v e

f^{'} (- 1) = \frac{1 + e - 3 e^{- 1}}{e^{- 1} + 1} = + v e

Critical point in

(- 1, 0)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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Let y(x) be a solution of the differential equation 1+ex y′+yex=1. If y0=2 , then which of the following statements is (are) true?

Step-by-step Solution

Let $y (x)$ be a solution of the differential equation $(1 + e^{x}) y^{'} + y e^{x} = 1 .$ If $y (0) = 2$ , then which of the following statements is (are) true?